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Calculation of compression indicators C10, C25 and C50. These are defined as the narrowest age intervals in which resp. 10, 25 and 50 percent of all deaths occur.
Example: France, female, 1991-95.
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| Table A |
| x |
d(x) |
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| 80 |
2954 |
| 81 |
3207 |
| 82 |
3482 |
| 83 |
3788 |
| 84 |
4044 |
| 85 |
4218 |
| 86 |
4386 |
| 87 |
4510 |
| 88 |
4561 |
| 89 |
4540 |
| 90 |
4421 |
| 91 |
4207 |
| 92 |
3903 |
| 93 |
3505 |
| 94 |
3044 |
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| Table B. |
| No. |
d(x) |
d(x) |
required |
indicator |
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| 1 |
4561 |
4561 |
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| 2 |
4540 |
9101 |
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| 3 |
4510 |
13611 |
10000 |
C10 |
| 4 |
4421 |
18032 |
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| 5 |
4386 |
22418 |
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| 6 |
4218 |
26636 |
25000 |
C25 |
| 7 |
4207 |
30843 |
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| 8 |
4044 |
34887 |
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| 9 |
3903 |
38790 |
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| 10 |
3788 |
42578 |
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| 11 |
3505 |
46083 |
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| 12 |
3482 |
49565 |
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| 13 |
3207 |
52772 |
50000 |
C50 |
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Procedure:
Table A gives the part of the age-at-death distribution required for Table B. The series has to be smooth enough so that the d(x) values decline regularly on both sides of the mode.
Table B gives the d(x) values in a contiguous area on both sides of the mode, in descending order. These are summed up until the total reaches 50000.
Each indicator equals the number of years needed for the resp. total, less the fraction of the last-added year which exceeds the specified total.
Solution:
C10 = 3-3611/4510 = 2.20 years.
C25 = 6-1636/4218 = 5.61 years.
C50 = 13-2772/3207 = 12.14 years.
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